Respuesta :
Answer:
15.56%
Step-by-step explanation:
The force applied, F, to the surface is 90N.
The area, A, of the surface is [tex]20 cm^2[/tex] = [tex]0.002m^2[/tex]
The pressure on the surface is:
P = F / A = 90 / 0.002 = 45000 Nm^2
The force is increased by 5N, the new force is 95N.
The surface area is increased by 5 cm^2 = 0.0005 m^2. The new surface area is 0.0025 m^2.
The pressure is now:
P = 95 / 0.0025 = 38000 Nm^2
The percentage decreased is gotten by dividing the difference in the two values by the old value and then multiplying by 100.
=> Difference = 45000 - 38000 = 7000
% decrease is therefore:
= 7000 / 45000 * 100 = 15.56%
There was a 15.56% decrease.
The ratio of the applied force to the area to which the force is applied,
gives the amount of pressure applied.
The outcome decreases by [tex]\underline{15.\overline 5 \%}[/tex]
Reasons:
[tex]\mathrm{Pressure, P} = \dfrac{Force, \, F}{Area, \, A}[/tex]
The initial force, F₁ = 5 N
The initial area, A₁ = 20 cm²
[tex]\mathrm{ } P_1=\dfrac{F_1}{A_1 }[/tex]
[tex]\mathrm{The \ initial \ pressure \ on \ the \ surface \ is \ } P_1=\dfrac{90 \ N}{0.002 \ m^2} = 45,000 \ Pa[/tex]
The new force, F₂ = F₁ + 5 N = 90 N + 5 N = 95 N
The new area, A₂ = A₁ + 5 cm² = 20 cm² + 5 cm² = 25 cm²
The new pressure after the increase is given by the equation;
[tex]\mathrm{ } P_2=\dfrac{F_2}{A_2 }[/tex]
[tex]\mathrm{The \ surface \ pressure \ after \ the \ increase\ is \ } P_2=\dfrac{95 \ N}{0.0025 \ m^2} = \mathbf{38,000 \ Pa}[/tex]
[tex]Percentage \ change = \dfrac{New \ value - Initial \ value}{Initial \ value} \times 100[/tex]
[tex]Percentage \ change = \dfrac{38,000 - 45,000}{45,000} \times 100 = 15.\overline 5 \%[/tex]
The outcome decreases by 15.[tex]\overline 5 \%[/tex]
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