Answer:
The intensity of the light that passes through a polarizer is 0.55I₀.
Explanation:
The intensity of the light that passes through a polarizer can be found using Malus's law:
[tex] I = I_{0}cos^{2}(\theta) [/tex]
Where:
I: is the intensity of the light that passes through a polarizer
I₀: is the initial intensity
θ: is the angle between the light's initial polarization direction and the axis of the polarizer = 42°
[tex] I = I_{0}cos^{2}(\theta) = I_{0}cos^{2}(42) = 0.55*I_{0} [/tex]
Therefore, the intensity of the light that passes through a polarizer is 0.55I₀.
I hope it helps you!
