Respuesta :
Answer:
In city one, the hotel charges before taxes were $5,250.
In city two, the hotel charges before taxes were $6,750.
Step-by-step explanation:
Let the hotel charge in the first city be x and in the second city be y.
Given that the hotel charge before tax in the second city was $ 1500 higher than in the first. That can be written as:
[tex]y - x = \$1500[/tex] ...[1]
The tax in the first city was 5 %, and the tax in the second city was 8.5 %.
The total hotel tax paid for the two cities was $ 836.25
5% of x + 8.5% of y = $836.25
[tex]0.05x+0.085y=\$836.25[/tex]...[2]
Now putting value of y from [1] in to [2]:
[tex]y = \$1500+x[/tex]
[tex]0.05x+0.085\times (\$1500+x)=\$836.25[/tex]
On solving we get :
x = $5,250
Using vakue of x in [1] to find y:
[tex]y=\$1500+\$5,250=\$ 6,750[/tex]
In city one, the hotel charges before taxes were $5,250.
In city two, the hotel charges before taxes were $6,750.
