Answer:
(a)2.865 s
(b)2.865 s
Explanation:
We are given that
Acceleration,a=[tex]3.49 m/s^2[/tex]
a.Initial speed,u=29 m/s
Final speed,v=39 m/s
We know that
[tex]t=\frac{v-u}{a}[/tex]
Using the formula
[tex]t=\frac{39-29}{3.49}=2.865 s[/tex]
b.Initial speed,u=59 m/s
Final speed,v=69 m/s
Again using the formula
[tex]t=\frac{69-59}{3.49}=2.865 s[/tex]