Answer:
[tex]9.7\times 10^{-4}\ rad/s[/tex]
Explanation:
Given:
[tex]m=500 kg\\F=3000 N[/tex]
[tex]Radius of earth , R=6371 \times 10^3\ m\\Angular speed =\omega\\We\ know\ that\ \\F= m\times \omega^{2} \times R\\\omega^{2}=\frac{F}{m*R} \\\\=\frac{3000}{500*6371 \times 10^3\ m}[/tex]
=[tex]\frac{6}{6371 \times 10^3\ m}[/tex]
=[tex]9.7\times 10^{-4}\ rad/s[/tex]
