kcmullen2002
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The solubility of Z is 60 g/ 100 g water at 20 °C. How many grams of solution are produced when a saturated solution is prepared using 300 grams of water at the same temperature? a 240 b 180 c 120 d 480

Respuesta :

Answer:

Saturated solution = 180 gram

Explanation:

Given:

Solubility of Z = 60 g / 100 g water

Given temperature =  20°C

Amount of water = 300 grams

Find:

Saturated solution

Computation:

Saturated solution = [Solubility of Z] × Amount of water

Saturated solution = [60 g / 100 g] × 300 grams

Saturated solution = [0.6] × 300 grams

Saturated solution = 180 gram

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