In triangle △JKL, ∠JKL is right angle, and KM is an altitude. JL=25 and JM=5, find KM.
HELP ME PLEASE!!!!!!

Answer:
KM = 15
Step-by-step explanation:
From the diagram, ΔJKL and ΔJKM are similar to each other because they share the same angle J and they are both right angle triangle. Therefore they are similar by AA property.
Since JL=25 and JM=5, JM = JL + JM= 25 + 5 = 30
Since ΔJKL and ΔJKM are similar to each other, therefore:
[tex]\frac{JK}{JL}=\frac{JM}{JK}\\ Substituting:\\\frac{JK}{30}=\frac{5}{JK}\\JK^2=150\\JK=\sqrt{150}\\ \\From\ hypotenuse:\\JK^2=JM^2+KM^2\\Substituting:\\(\sqrt{150} )^2=5^2+KM^2\\150=25+KM^2\\KM^2=150-25=125\\KM=\sqrt{125}\\ KM=15[/tex]