Answer:
d=1
Step-by-step explanation:
Factor d^2 - 2d - 8 into (d-4)(d+2)
Move -2/d+2 onto the other side, changing it into 2/d+2.
[tex]\frac{-3d}{(d-4)(d+2)} +\frac{3}{d-4}+\frac{2}{d+2} = 0[/tex]
Let the empty side equal zero.
Add 3/d-4 and 2/d+2
[tex]\frac{5d-2}{(d+2)(d-4)}[/tex]
Then add that to -3d.
[tex]\frac{2d-2}{(d+2)(d+4)}[/tex]
Multiply 0 by d+2 and d-4 to get 2d-2 by itself.
2d=2
d=1
I can't edit the equation, but it's d-4 althroughout the question. Sorry for being so slow.
