A car accelerates uniformly from 36 km/h to 72 km/h in 2 seconds. Calculate :a.The acceleration of the car b.The distance covered by the car in that time.

Respuesta :

Answer:

(a) The acceleration of the car is 5 m/s²

(b) The distance covered by the car in that time is 30 m

Step-by-step explanation:

Given;

initial velocity of the car, u = 36 km/h = 10 m/s

final velocity of the car, v = 72 km/h = 20 m/s

time for the motion, t = 2 seconds

(a) .The acceleration of the car;

v = u + at

[tex]a = \frac{v-u}{t} \\\\a = \frac{20-10}{2}\\\\a = 5 \ m/s^2[/tex]

(b) The distance covered by the car in that time

[tex]s = (\frac{v+u}{2} )t\\\\s = (\frac{20+10}{2} )*2\\\\s = 30 \ m[/tex]