Answer:
0.2196
Step-by-step explanation:
Given that
Mean = 4.56 million visitors per day
Standard deviation = 820,000 visitors per day
According to the given situation the calculation of probability is shown below:-
Here we will find the value of P (3 ≤ X ≤ 4)
[tex]P 93\leq X\leq 4)=P(X\leq 4) - P(X\leq 3)[/tex]
[tex]\\=P(\frac{X-\mu}{\sigma}\leq \frac{4-4.56}{0.82})-P(\frac{X-\mu}{\sigma}\leq \frac{3-4.56}{0.82})[/tex]
[tex]\\=P(Z\leq -0.683)-P(Z\leq -1.9024[/tex]
= 0.2483 - 0.0287
= 0.2196
Therefore the probability that the web site has between 3 million and 4 million visitors in a single day is 0.2196
