The length of a rectangular pool is 4yds longer than twice the width. If the area is 70 square yards, find the dimensions.

Respuesta :

Answer: Found it by web and solving

Step-by-step explanation: L = W + 4

LW = 60

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LW = 60

(W + 4)W = 60

W^2 + 4W + (-60) = 0

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above is in quadratic equation form: ax^2 + bx + c = 0

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use the quadratic formula to solve for two solutions:

x = ( -b +- sqrt( bb - 4ac ) ) / 2a

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the two solutions are:

W = 6

W = -10

 

the negative solution doesn't make sense for length, so use the positive solution.

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L = 10

W = 6

L is equal to 10
W is equal to 6