Answer:
Any point, Q, along segment CD is equidistant from S and T.
Step-by-step explanation:
Bisection involves dividing a line or angle into two equal parts. A perpendicular bisector of a line is always at right angle to the said line.
Given line ST and a bisector CD. This implies that segment CD divide ST into two equal parts. Any point Q has equal distance from S and T. Therefore, any point, Q, along segment CD is equidistant from endpoints S and T.