Answer:
[tex]8.339\ m/s[/tex]
Explanation:
Given :
[tex]m1= 1400 kg \\v1=13.7 m/s\\m2=3200 kg \\v2=0[/tex]
We know that for the elastic collision
[tex]V2=\frac{2m1v1}{m1+m2} \ + \frac{m2-m1 * v2}{m1+m2}[/tex]
Putting the respective value we get
[tex]V2=\frac{2*1400*13.7}{1400+3200} \ + 0\\ V2=8.339\ m/s[/tex]