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A cylinder contains 27.0 L of oxygen gas at a pressure of 1.7 atm and a temperature of 285 K . Part A How much gas (in moles) is in the cylinder? Express your answer using two significant figures.

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sebassandin

Answer:

[tex]n=2.0mol[/tex]

Explanation:

Hello.

In this case, we should use the ideal gas equation in order to compute the the moles of oxygen at the given conditions of 27.0 L, 1.7 atm and 285 K as shown below:

[tex]PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.7atm*27.0L}{0.082\frac{atm*L}{mol*K}*285K}\\ \\n=2.0mol[/tex]

Best regards.

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