Answer:
f^-1(x) is 6x + 48
f(x) = 1/6x - 8
To find f^-1(x) equate f(x) to y
That's
f(x) = y
y = 1/6x - 8
Next interchange the terms
We have
x = 1/6y - 8
Make y the subject
Multiply through by 6
We have
6x = y - 48
y = 6x + 48
Therefore f^-1(x) is 6x + 48
Hope this helps you
