Answer:
[tex]n_{K^+}=0.0009molK^+[/tex]
Explanation:
Hello,
In this case, the first step is to compute the number of moles of potassium phosphate in 20.0 mL (0.020L) of the 0.015-M (mol/L) solution as shown below:
[tex]n=0.020L*0.015\frac{mol}{L}=0.0003mol[/tex]
Thus, these moles correspond to potassium phosphate moles, which molecular formula is K₃PO₄, therefore, one mole of this compound contains three moles of potassium ions as it has three as its subscript in the formula. Thereby, the moles of potassium ions result in:
[tex]n_{K^+}=0.0003molK_3PO_4*\frac{3molK^+}{1molK_3PO_4} \\\\n_{K^+}=0.0009molK^+[/tex]
Best regards.
