Answer:
[tex]\boxed{\sf \ \ \ f^{-1}(x)=\dfrac{x+7}{3} \ \ \ }[/tex]
Step-by-step explanation:
hello
f(x)=3x-7
what can we say about [tex]f^{-1}(x) ?[/tex]
[tex](fof^{-1})(x)=x=f(f^{-1}(x))=3f^{-1}(x)-7[/tex]
so
[tex]3f^{-1}(x)-7=x\\<=> 3f^{-1}(x)-7+7=3f^{-1}(x)=x+7 \ \ \ add \ \ 7\\ <=> f^{-1}(x)=\dfrac{x+7}{3} \ \ \ divide \ \ by \ \ 3[/tex]
hope this helps
