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In ∆ABC the angle bisectors drawn from vertices A and B intersect at the point D. Find m∠ADB if:
m∠A = α, m∠B = β

Respuesta :

Answer:

Pretty easy (if you know geometry)!

Step-by-step explanation:

First, we know that A and B have angle bisectors. This means the angles that are divided by that angle bisector are equal (or their measures).

Thus, m<DBA= 1/2 Beta; m<DAB=1/2 Alpha.

Time to find m<ADB. Using the sum of all angles in a triangle = 180* theorem, we can come up with this equation:

[tex]180= m<ADB+\frac{1}{2} \alpha +\frac{1}{2} \beta[/tex]

So, solving:

[tex]180-\frac{1}{2} \alpha -\frac{1}{2} \beta =m<ADB[/tex]

So there you go! Hope this helps!

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