Answer:
c) [tex]2\frac{23}{30}[/tex] d)[tex]1\frac{23}{24}[/tex]
7) a. [tex]6\frac{3}{11}[/tex] kg b. [tex]6 \frac{2}{3}[/tex] cm c. 20 cm
d. [tex]9\frac{9}{10}[/tex] kg e. 10 g f. [tex]23 \frac{1}{4}[/tex] kg
Step-by-step explanation:
c) [tex]8\frac{2}{3}[/tex] - [tex]5\frac{9}{10}[/tex]
First we will change to improper fraction and then solve
[tex]\frac{26}{3} - \frac{59}{10}[/tex]
= [tex]\frac{260 - 177}{30}[/tex]
= [tex]\frac{83}{30}[/tex]
we will now change to mixed number
= [tex]2\frac{23}{30}[/tex]
d) [tex]8\frac{1}{8} - 6\frac{1}{6}[/tex]
we will first change it to improper fraction and then solve
= [tex]\frac{65}{8} - \frac{37}{6}[/tex]
= [tex]\frac{390 - 296}{48}[/tex]
= [tex]\frac{94}{48}[/tex]
we can reduce the fraction
=[tex]\frac{47}{24}[/tex]
we will change it mixed number
=[tex]1\frac{23}{24}[/tex]
7)
a. [tex]\frac{3}{11}[/tex] of 23
= [tex]\frac{3}{11}[/tex] × 23
= [tex]\frac{69}{11}[/tex]
=[tex]6\frac{3}{11}[/tex] kg
b. [tex]\frac{2}{3}[/tex] of 10 cm
= [tex]\frac{2}{3}[/tex] × 10 cm
= [tex]\frac{20}{3}[/tex] cm
=[tex]6 \frac{2}{3}[/tex] cm
c. [tex]\frac{5}{6}[/tex] of 24cm
= [tex]\frac{5}{6}[/tex] × 24 cm
6 will divide 24
=5 × 4 cm
= 20 cm
d. [tex]\frac{3}{10}[/tex] of 33 kg
= [tex]\frac{3}{10}[/tex] × 33 kg
=[tex]\frac{99}{10}[/tex] kg
=[tex]9\frac{9}{10}[/tex] kg
e. [tex]\frac{2}{7}[/tex] of 35 g
= [tex]\frac{2}{7}[/tex] × 35 g
7 will go into 35
=2×5 g
=10 g
f. [tex]\frac{3}{4}[/tex] of 31 kg
= [tex]\frac{3}{4}[/tex] × 31 kg
=[tex]\frac{93}{4}[/tex] kg
=[tex]23 \frac{1}{4}[/tex] kg
