Answer:
5
Step-by-step explanation:
[tex] \because \triangle ACB \cong \triangle DCE... (given) \\
\therefore \angle A \cong \angle D... (c.a.c.t)\\
\therefore m\angle A = m\angle D\\
\therefore 50\degree = 10x\\\\
\therefore x = \frac{50\degree}{10}\\\\
\huge \orange {\boxed {\therefore x = 5\degree}} [/tex]
