an object weighting 100g is thrown upwards from the ground at a speed of 100 m/s.where will the potential energy of the object be two thirds of the kinetic energy?

Respuesta :

Answer:

333.3 m

Explanation:

Given

[tex]m =100g\ =\ 0.1kg\\v = 100 m/s\\g = 10 m/s ^2[/tex]

Potential energy =[tex]\frac{2}{3}\ of\ Kinetic\ energy[/tex]......Equation(1)

We know that

Potential energy=mgh

Kinetic energy =[tex]\frac{1}{2} mv^{2}[/tex]

Now From the Equation(1)

[tex]mgh=\frac{2}{3}*\frac{1}{2} mv^{2}\\ gh=\frac{v^{2} }{3} \\10 * h=\ \frac{10000}{3}\\ h=\ \frac{1000}{3} \\h=333.3\ m[/tex]