Respuesta :
Answer:
[tex]y = x^3 - 7x^2 + 121x + 847[/tex]
Step-by-step explanation:
If -11i is a zero, its conjugate also is a zero, so the zeros are:
7, 11i and -11i.
So we can write the third degree function as:
[tex]y = a(x-7)(x-11i)(x+11i)[/tex]
[tex]y = a(x-7)(x^2+121)[/tex]
If the function has a value of 663 when x = 10, we have:
[tex]663 = a(10-7)(10^2+121)[/tex]
[tex]663 = a(3)(221)[/tex]
[tex]a = 663/663 = 1[/tex]
So the function is:
[tex]y = (x-7)(x^2+121)[/tex]
[tex]y = x^3 - 7x^2 + 121x - 847[/tex]
