The value of n in improper fraction is [tex]\frac{\sqrt{2} }{32}[/tex]
The given parameters;
[tex]\frac{1}{8}[/tex] ÷ [tex]\sqrt{2}[/tex] = 2n
The value of n in improper fraction is obtained by simplifying the equation as shown below;
[tex]\frac{1}{8} \times \frac{1}{\sqrt{2} } = 2n\\\\\frac{1}{8\sqrt{2} } = 2n\\\\\frac{1}{\sqrt{8^2 \times 2} } = 2n\\\\\frac{1}{\sqrt{128} } = 2n\\\\\frac{1}{2 \times \sqrt{128} } = n\\\\\frac{1}{ \sqrt{4\times 128} } = n\\\\\frac{1}{ \sqrt{512} } = n\\\\\frac{1}{\sqrt{256 \times 2} } = n\\\\\frac{1}{16\sqrt{2} } = n\\\\\frac{1 }{16\sqrt{2} } \times \frac{\sqrt{2} }{\sqrt{2} } = n\\\\\frac{\sqrt{2} }{32} = n[/tex]
Thus, the value of n in improper fraction is [tex]\frac{\sqrt{2} }{32}[/tex]
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