Answer:
see explanation
Step-by-step explanation:
Given
y = x² - 6x + 2
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
To complete the square
add/subtract ( half the coefficient of the x- term )² to x² - 6x
y = x² + 2(- 3)x + 9 - 9 + 2
= (x - 3)² - 7 ← in vertex form
with vertex = (3, - 7 ) and a = 1
Since a > 0 then vertex is a minimum
