Answer:
[tex]\frac{2x - 2}{x^2+3x-4}[/tex]
Step-by-step explanation:
In the figure attached, the question is shown. The function:
[tex]\frac{2x - 2}{x^2+3x-4}[/tex]
has a horizontal asymptote at y = 0 because the degree of the nominator polynomial is less than the degree of the denominator polynomial.
The roots of x² + 3x - 4 are -4 and 1
Then, x² + 3x - 4 = (x + 4)(x - 1)
The function has a vertical asymptote at x = -4 because it is a root of the denominator polynomial.
The function can be simplified as follows:
[tex]\frac{2(x - 1)}{(x+4)(x-1)}[/tex]
[tex]\frac{2}{x+4}[/tex]
Then, it has a removable discontinuity at x = 1
