Answer:
The weight of Shanu's dog now is 21.375 pounds.
Step-by-step explanation:
We are given that Shaun's dog weighs 22 One-fourth pounds. Shaun weighed the dog after one week and found she had lost Seven-eighths of a pound.
And we have to find the weight of the dog after exercise.
The Original weight of Shaun's dog = [tex]22 \frac{1}{4}\text{ pounds}[/tex]
Converting the above mixed fraction into an improper fraction we get;
[tex]22\frac{1}{4} = \frac{(22 \times 4)+1}{4}[/tex]
= [tex]\frac{89}{4} \text{ pounds}[/tex]
Now, it is stated that after walking an extra mile every day, Shanu's dog lost Seven-eighths of a pound, that is = [tex]\frac{7}{8} \text{ pound}[/tex]
So, the weight of Shanu's dog now = Original weight - Weight after exercise
= [tex]\frac{89}{4}-\frac{7}{8}[/tex]
Making denominator same for both the fractions;
= [tex]\frac{89\times 2}{4\times 2}-\frac{7\times 1}{8\times 1}[/tex]
= [tex]\frac{178}{8}-\frac{7}{8}[/tex]
= [tex]\frac{178-7}{8}[/tex]
= [tex]\frac{171}{8}[/tex] = 21.375 pounds.
Hence, the dog weigh 21.375 pounds now.
