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The school designed their rectangular vegetable garden to have a perimeter of 32 feet
with the length measuring 2 feet more than twice the width. Using y to represent the
length of the garden and w to represent its width, write and solve a system of equations
that describes this situation. What are the dimensions of the garden

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Answer:

The dimensions are 10 2/3 feet by 5 1/3 feet (Ten and two-thirds and five and one third).

Step-by-step explanation:

This is our system of equations:

y=Length

x=Width

y=2x

2x+2y=32

We can substitute the y value in the second equation by plugging in the first equation:

2x+2(2x)=32

2x+4x=32

6x=32

x=16/3 or 5 1/3

We can plug in this x value into the first equation to find the y value:

y=2(16/3)

y=32/3 or 10 2/3

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