Respuesta :
Answer:
[tex] X(t)= 24 cos (6.28 t +1.57)[/tex]
And for this case we can write this expression like this:
[tex] X(t) =A cos (wt +\phi)[/tex]
The velocity would be given by the first derivate and we got:
[tex] V(t) = -wA sin (wt +\phi)[/tex]
And the maximum velocity would be:
[tex]V_{max}= |6.28 *24| = 150.72 m/s[/tex]
Explanation:
For this case we have the following function for the position:
[tex] X(t)= 24 cos (6.28 t +1.57)[/tex]
And for this case we can write this expression like this:
[tex] X(t) =A cos (wt +\phi)[/tex]
The velocity would be given by the first derivate and we got:
[tex] V(t) = -wA sin (wt +\phi)[/tex]
And the maximum velocity would be:
[tex]V_{max}= |6.28 *24 |= 150.72 m/s[/tex]
