Respuesta :
Answer:
The height of parallelogram is [tex]2x^2-7x+1[/tex]
Step-by-step explanation:
Area of parallelogram =[tex]Base \times Height[/tex]
Area of parallelogram = [tex]2x^3 -x^2 -20x + 3[/tex]
Base of parallelogram = x+3
So, [tex]2x^3-x^2-20x + 3 = height \times (x+3)[/tex]
[tex]\frac{2x^3- x^2 -20x + 3}{x+3}= height\\2x^2-7x+1=Height[/tex]
Hence The height of parallelogram is [tex]2x^2-7x+1[/tex]
