Richard made tables of values to solve a system of equations. First he found
that the x-value of the solution was between 0 and 1, and then he found that it
was between 0.5 and 1. Next, he made this table.

Richard made tables of values to solve a system of equations First he found that the xvalue of the solution was between 0 and 1 and then he found that it was be class=

Respuesta :

Answer:

(0.9,4.2)

Step-by-step explanation:

Given:

The table above such that

[tex]y = -x + 5[/tex]

[tex]y = 6x - 1[/tex]

Required

Approximation of the solution

To do this, we start by equating both values of y

[tex]-x + 5 = 6x - 1[/tex]

Collect like terms

[tex]-x - 6x = -5 -1[/tex]

[tex]-7x = -6[/tex]

Divide both sides by -7

[tex]\frac{-7x}{-7} = \frac{-6}{=7}[/tex]

[tex]x = \frac{6}{7}[/tex]

[tex]x = 0.8571[/tex]

[tex]x = 0.9[/tex] (Approximated)

Substitute [tex]\frac{6}{7}[/tex] for x in any of the expression of y

Using [tex]y = -x + 5[/tex]

[tex]y = -\frac{6}{7}+ 5[/tex]

[tex]y = \frac{-6+35}{7}[/tex]

[tex]y = \frac{29}{7}[/tex]

[tex]y = 4.1[/tex] (Approximated)

The closest to this is option D

(x,y) = (0.9,4.2)