Respuesta :
448 K is the final temperature of the water.
What is specific heat capacity?
The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).
Given the mass of Na is 23 g
The volume of water = 293 cm3
Mass of water = 293 g
Total solution mass = 23 g + 293 g = 316 g
Specific heat capacity of water = 4.18 J/K.g
The equation relating mass, heat, specific heat capacity and temperature change is:
q = mcΔT
197 kJ = 316 g x 4.18 J/Kg x ([tex]T_{final} -T_{initial}[/tex])
197 kJ = 316 g x 4.18 J/Kg x ([tex]T_{final}[/tex] -298 K)
0.1491429956 x 1000 = [tex]T_{final}[/tex]-298 K)
149.1429956 + 298 = [tex]T_{final}[/tex]
447.1429956 =[tex]T_{final}[/tex]
448 K =[tex]T_{final}[/tex]
Hence, 448 K is the final temperature of the water.
Learn more about specific heat capacity here:
https://brainly.com/question/2530523
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