Respuesta :
Answer:
c. 15 g Kr
Explanation:
The amount of a gas (Moles) is directely proportional to its pressure. That means the higher amount of moles, the highest pressure and vice versa.
Using molar mass of the compounds (Ne=20.2g/mol, Ar = 39.9g/mol, Kr = 83.8g/mol, CO₂ = 44 g/mol and F₂ = 38.0g/mol), moles of 15.0g of each gas are:
Ne = 15g ₓ (1mol / 20.2g) = 0.74 moles of Ne
Ar = 15g ₓ (1mol / 39.9g) = 0.38 moles of Ar
Kr = 15g ₓ (1mol / 83.8g) = 0.18 moles of Kr
CO₂ = 15g ₓ (1mol / 44g) = 0.34 moles of CO₂
F₂ = 15g ₓ (1mol / 38g) = 0.39 moles of F₂
As 15g of Kr contains the less quantity of moles, this sample will con have the lowest pressure
The sample with the lowest pressure has been 15 g Krypton. Thus option C is correct.
The following samples have been corresponded to be the ideal gas. The ideal gas equation can be given as:
Pressure [tex]\times[/tex] Volume = moles
Since all the gases have the same temperature and volume, and R has been constant, the pressure of the gas has been directly proportional to the moles of the gases.
Pressure = Moles
Thus, the gas with the highest moles has the highest pressure.
Moles can be expressed as:
Moles = [tex]\rm \dfrac{weight}{molecular}[/tex]
- Moles of 15 grams Ne:
Moles of Ne = [tex]\rm \dfrac{15}{20.1797}[/tex] mol
Moles of Ne = 0.743 mol.
- Moles of 15 g Kr:
Moles of Kr = [tex]\rm \dfrac{15}{83.798}[/tex]
Moles of Kr = 0.179 mol.
- Moles of [tex]\rm \bold{CO_2}[/tex]:
Moles of [tex]\rm CO_2[/tex] = [tex]\rm \dfrac{15}{44.01}[/tex]
Moles of [tex]\rm CO_2[/tex] = 0.34 mol.
- Moles of [tex]\rm \bold{F_2}[/tex]:
Moles of [tex]\rm F_2[/tex] = [tex]\rm \dfrac{15}{37.998}[/tex]
Moles of [tex]\rm F_2[/tex] = 0.394 mol.
The sample with the lowest number of moles has been 15 g of Krypton. Thus the sample with the lowest pressure has been 15 g Krypton. Thus option Cis correct.
For more information about pressure at a constant temperature, refer to the link:
https://brainly.com/question/12152879