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How many liters of a 1 M NaOH stock solution would you need to make 785 mL of a 215 mM NaOH dilution? (m.w. = 40.00 g/mol) Do not include units in your answer; report your answer in the requested units.

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jufsanabriasa

Answer:

0.1688L of the 1M NaOH stock solution

Explanation:

A 215mM = 0.215M solution of NaOH contains 0.215 moles per liter. As you want to prepare 785mL = 0.785L of the 0.215M you will need:

0.785L × ( 0.215mol / L) = 0.1688 moles of NaOH.

These moles of NaOH comes from the 1M stock solution, that means the volume of 1M NaOH solution you need is:

0.1688 moles NaOH × (1L / 1mol) =

0.1688L of the 1M NaOH stock solution

Eduard22sly

The volume of the stock solution of 1 M NaOH stock solution needed to make 785 mL of a 215 mM NaOH dilution is 0.169 L

From the question given above, the following data were obtained:

Molarity of stock (M₁) = 1 M

Volume of diluted solution (V₂) = 785 mL = 785 / 1000 = 0.785 L

Molarity of diluted solution (M₂) = 215 mM = 215 / 1000 = 0.215 M

Volume of stock solution needed (V₁) =?

The volume of the stock solution needed can be obtained as follow:

M₁V₁ = M₂V₂

1 × V₁ = 0.215 × 0.785

V₁ = 0.169 L

Therefore, the volume of the stock solution needed is 0.169 L

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