Answer:
33 %
Explanation:
Step 1: Given data
Initial moles of the acid (nHA(0)): 6 mol
Moles of the conjugate base at equilibrium (nA⁻(eq))
Step 2: Write the balanced generic acid dissociation reaction
HA(aq) ⇄ A⁻(aq) + H⁺(aq)
Step 3: Calculate the percent ionization
We will use the following expression.
[tex]\alpha = \frac{nA^{-}(eq)}{nHA(0)} \times 100 \% = \frac{2mol}{6mol} \times 100 \% = 33 \%[/tex]
