Suppose that the distribution of lifetimes of females in France is not symmetric. According to Chebyshev's Theorem, at least approximately what percentage of these lifetimes are within k=3.8 standard deviations of the mean?

Respuesta :

Answer:

93.7%  of the lifetimes  are within 3.8  standard deviations of the mean  

Step-by-step explanation:

   Generally Chebyshev's Theorem, can be mathematically represented as  

   [tex]1 - \frac{1}{k^2}[/tex]%

The percentage  of these lifetimes that are within k=3.8 standard deviations of the mean is mathematically  evaluated using Chebyshev's Theorem as follows      

        [tex]1 - \frac{1}{k^2}[/tex]%  [tex]= (1 - \frac{1}{3.8^2} )[/tex]% =  [tex]= 93.07[/tex]%

So from the above calculation we see that 93.7%  of the lifetimes  are within 3.8  standard deviations of the mean