Answer:
[tex]\mathbf{H_2PO^{-}_4}[/tex] and [tex]\mathbf{HPO^{2-}_4}[/tex] are the amphoteric species.
Explanation:
Phosphorus is a non-metallic element belonging to Group 5 of the Periodic table. As a triprotic acid (i.e an acid that has three dissociable protons that undergo stepwise ionization) . Phosphorus reacts vigorously with hot water to form tetraoxosulphate(V) acid.
i.e
[tex]P_4O_{10(s)} + 6 H_2O_{l} \to4H_3PO_{4(aq)}[/tex]
SO;
As a triprotic acid;
The ionization equations are as follows:
NOTE: Instead of the amphoteric species to be circle as instructed , due to the fact that we are using the LaTex Editor ; we will just need to let them be in bold format which will differentiate them from the rest.
[tex]H_3PO_{4} \leftrightarrow H^+ + H_2PO^{-}_4[/tex]
[tex]\mathbf{H_2PO^{-}_4} \leftrightarrow H^+ + HPO^{2-}_4[/tex]
[tex]\mathbf{HPO^{2-}_4} \leftrightarrow H^+ + PO^{3-}_4[/tex]
Thus; [tex]\mathbf{H_2PO^{-}_4}[/tex] and [tex]\mathbf{HPO^{2-}_4}[/tex] are the amphoteric species.
