The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 58-m-diameter loop-the-loop. What is the car's speed at the top?

Respuesta :

Answer:

16.87 m/s

Explanation:

To find the speed of the car at the top, when the normal force is equal the gravitational force, we just need to equate both forces:

[tex]N = P[/tex]

[tex]m*a_c = mg[/tex]

[tex]a_c[/tex] is the centripetal acceleration in the loop:

[tex]a_c = v^2/r[/tex]

So we have that:

[tex]mv^2/r = mg[/tex]

[tex]v^2/r = g[/tex]

[tex]v^2 = gr[/tex]

[tex]v = \sqrt{gr}[/tex]

So, using the gravity = 9.81 m/s^2 and the radius = 29 meters, we have:

[tex]v = \sqrt{9.81 * 29}[/tex]

[tex]v = \sqrt{284.49} = 16.87\ m/s[/tex]

The speed of the car is 16.87 m/s at the top.