Answer:
0.46
Explanation:
We can solve this problem using the suvat equations of motions.
the height, s is what we are trying to find out
initial velocity, u = 3 m/s from the question
final velocity, v = 0 m/s since it hits the ground it will stop moving downwards
acceleration, a = -9.81, due to gravity
time, t =7, from the question.
v² = u² + 2as ⇒ v²-u² = 2as
⇒ s = [tex]\frac{v^{2} -u^{2} }{2a}[/tex]
⇒ s = [tex]\frac{0^{2} -3^{2} }{-19.62}[/tex]
⇒ s = 9/19.62
⇒ s ≈ 0.46
