Answer:
[tex]\angle\,A=72^o\\\angle\,B=108^o[/tex]
Step-by-step explanation:
Notice that buy construction of a parallelogram,the angles [tex]\angle \,A[/tex] and [tex]\angle \,C[/tex] must equal each other. Then, based on the info given, we can write the following equation:
[tex]3\,y+27^o=5\,y-3^o\\27^o+3^o=5\,y-3\,y\\30^o=2\,y\\y=15^o[/tex]
Then, angle [tex]\angle \,A[/tex] =[tex]5\,(15^o)-3^o=72^o[/tex] which is also equal to angle B
and since the addition of all internal angles of the parallelogram must equal [tex]360^o[/tex] , then:
[tex]B+D=360^o-72^o-72^o=216^o[/tex]
and therefore, since [tex]\angle \,B[/tex] and [tex]\angle \,D[/tex] must be equal, then:
[tex]\angle\,B=\frac{216^o}{2} =108^o[/tex]
