Find the lateral area of the square pyramid shown to the nearest whole number.
25 yd
A
43 yd

Answer:
4,300
Step-by-step explanation:
Lateral area of a squared Pyramid is given as ½ × Perimeter of base (P) × slant height of pyramid
Thus, we are given,
Side base length (s) = 43 yd
height (h) = 25 yd
Let's find the perimeter
Permimeter = 4(s) = 4(43) = 172 yd
Calculate the slant height using Pythagorean theorem.
Thus, l² = s²+h²
l² = 43²+25² = 1,849+625
l² = 2,474
l = √2,474
l ≈ 50 yd
=>Lateral area = ½ × 172 × 50
= 172 × 25
= 4,300 yd