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GPAs at CCSU are normally distributed with a mean of 2.38 and a standard deviation of 0.45. Find the z-score for a GPA of 3.06. and discuss the significance of the z-score.

Respuesta :

Step-by-step explanation:

Z-score = (score-mean)/standard deviation

= (3.06-2.38)/0.45

= +1.51

The significance of z-score will be "1.5111".

Given values are:

Mean,

[tex]\mu = 2.38[/tex]

Standard deviation,

[tex]\sigma = 0.45[/tex]

GPA,

[tex]\bar x = 3.06[/tex]

Now,

→ The z-score will be:

= [tex]\frac{\bar x - \mu}{\sigma}[/tex]

By putting the given values, we get

= [tex]\frac{3.06-2.38}{0.45}[/tex]

= [tex]\frac{0.68}{0.45}[/tex]

= [tex]1.5111[/tex]

Learn more about standard deviation here:

https://brainly.com/question/5778359

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