Answer:
Conc = 1.64 Mol / dm3
Explanation:
We have to first put down the equation of the neutralization reaction. This is given as;
2HCl + Ca(OH)2 --> CaCl2 + 2H2O
This means that 2 mol of HCl requires 1 mol of Ca(OH)2.
2 = 1
x = 0.042
x = 0.084 mol of HCl required.
Volume = 51.21 ml = 0.05121 dm3
Concentration = Mass / Volume
Conc = 0.084 / 0.05121
Conc = 1.64 Mol / dm3
