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Suppose some of the solid calcium hydroxide is inadvertently transferred along with the supernatant liquid for analysis.

a. Will more, less, or the same amount of hydrochloric acid titrant be used for the analysis? Explain
b. How will this inadvertent transfer affect the calculated solubility product for Calcium Hydroxide? Explain
c. How will this inadvertent transfer affect the calculated molar solubility for the calcium hydroxide?Explain

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Answer:

Explanation:

a. Ca(OH)₂ + 2HCl -------> CaCl₂ + H₂O

if solid Ca(OH)₂ is transferred together with supernatant liquid, there is more Ca(OH)₂ than expected for saturated solution, more HCl titrant is used

b. Ca(OH)₂ <------> Ca₂ + 2OH⁻

the concentrations of OH⁻ and Ca²⁺ calculated will be higher, solubility product will also be higher

Ksp = [Ca²⁺][OH⁻]²

c. Since the concentrations of OH⁻ and Ca²⁺ will be higher, then, molar solubility calculated will also be higher

molar solubility = [Ca²⁺] = 1/2[OH⁻]

a. Amount of HCl is more.

b. Solubility product will be higher.

c. Molar solubility is also higher.

Solving for each part one by one:

a. Ca(OH)₂ + 2HCl -------> CaCl₂ + H₂O

If solid Ca(OH)₂ is transferred together with supernatant liquid, there is more Ca(OH)₂ than expected for saturated solution, more HCl titrant is used.

b. Ca(OH)₂ <------> Ca₂ + 2OH⁻

The concentrations of OH⁻ and Ca²⁺ calculated will be higher, solubility product will also be higher.

Ksp = [Ca²⁺][OH⁻]²

c. Since the concentrations of OH⁻ and Ca²⁺ will be higher, then, molar solubility calculated will also be higher.

Molar solubility = [Ca²⁺] = 1/2[OH⁻]

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