Answer:
power dissipated in the target is 100 W
Explanation:
given data
electrons = 1 mev = [tex]10^{6}[/tex] eV
1 eV = 1.6 × [tex]10^{-19}[/tex] J
current = 100 microampere = 100 × [tex]10^{-6}[/tex] A
solution
when energy of beam strike with 1 MeV so energy of electron is
E = e × v ...................1
e is charge of electron and v is voltage
so put here value and we get voltage
v = 1 ÷ 1.6 × [tex]10^{-19}[/tex]
v = [tex]10^{6}[/tex] volt
so power dissipated in target
P = voltage × current ..............2
put here value
P = [tex]10^{6}[/tex] × 100 × [tex]10^{-6}[/tex]
P = 100 W
so power dissipated in the target is 100 W
