Respuesta :

wegnerkolmp2741o

Answer:

We have 2 rational solutions

0 irrational solutions

0 complex solutions

Step-by-step explanation:

a^2 + 8a + 12 = 0

Using the discriminant

b^2 -4ac where ax^2 + bx+ c

so a =1  b = 8 and c = 12

8^2 -4(1)*12

64 - 48

16

Since the discriminant is greater than 0, we have 2 real solutions

since we can take the square root of 16, we have rational solutions

We have 2 rational solutions

Since this is a quadratic equations, there are only 2 solutions so there are

0 irrational solutions

0 complex solutions

Percivle

Answer:

2 Rational Solutions

0 Irrational Solutions

0 Complex Solutions

Step-by-step explanation:

The discriminant of the quadratic formula is the name given to the portion underneath the radical (or the square root)"

[tex]x = \frac{1}{2} (-b\frac{ + }{ - } \sqrt{ {b}^{2} - 4ac })[/tex]

Discriminant = D = b²-4ac

If D is less than 0 you have two complex solutions.

If D is equal to 0 you'll have one real solution.

If D is bigger than 0 you'll get two real solutions.

So here we have:

a=1

b=8

c=12

Which means D=64-4(1)(12)=64-48=16>0

D is bigger than 0, so you'll have two real solutions. And since 16 is a perfect square, they'll both be rational numbers.

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