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Six friends, four boys and two girls, went to a movie theater. They wanted to sit in a way so no girl sits on either first or last chair. How many such arrangements are possible?

Respuesta :

zubam2002

Answer:

120 ways

Step-by-step explanation:

Since no girl wil sit either first or last

Hence, in all irrespective whether boy or girl = (6 - 1)! = 5! = 5 X 4 X 3 X 2 = 120

∴ Number of arrangements = 120 ways

aac271

Answer:

288

Step-by-step explanation:

Dont have time to say anything, in a test, but trust me. I got it correct.

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