Answer:
a=k1[tex]\sqrt[3]{B}[/tex]
B=125
Step-by-step explanation:
Given :
a=3
B=64
According to question
a ∝ [tex]\sqrt[3]{B}[/tex]
therefore
a=k1 [tex]\sqrt[3]{B}[/tex]........Eq(1)
K1=[tex]\frac{a}{\sqrt[3]{B} }[/tex]......Eq(2)
Putting the value of a and B we get in Eq(2) we get
[tex]K1=\frac{3}{4}[/tex]
Putting the value of k1 in Eq(1)
[tex]a=\frac{3}{4}\sqrt{B}[/tex] .......................Eq(3)
putting the value of a=15/4 IN Eq(3) we get
[tex]\frac{15}{4}\ =\frac{3}{4} \sqrt[3]{B} \\\\\sqrt[3]{B}\ =\ 5\\Cubing\ both\ side\ we\ get\\B=125[/tex]
