Answer:
20π in³ or 62.832 in³
Step-by-step explanation:
The surface area for each cake is given by:
[tex]S=\pi r^2+2\pi rh[/tex]
Where 'r' is the radius of each cake (4 inches), and 'h' is the height of each cake (3 inches). Since there are two cakes, the total surface area is:
[tex]A=2*(\pi r^2+2\pi rh)\\A=2*(\pi 4^2+2\pi*4*3)\\A=80\pi\ in^2[/tex]
If Jayvon wants a consistent quarter-inch deep layer of frosting covering the surface of the cakes, the volume of frosting required is:
[tex]V=80\pi *0.25\\V=20\pi\ in^3 = 62.832\ in^3[/tex]
He needs 20π in³ or 62.832 in³ of frosting.
