Suppose the frequency of a note on an organ is 18 Hz. What is the shortest organ pipe with both ends open that will resonate at this frequency

Respuesta :

Answer:

9.53 m

Explanation:

The computation of shortest organ pipe with both ends open that will resonate at this frequency is shown below:-

[tex]\lambda = \frac{velocity}{frequency}[/tex]

[tex]= \frac{343}{18}[/tex]

= 19.06 m

Now the

Shortest organ pipe  with both ends open is

=  [tex]\frac{\lambda}{2}[/tex]

[tex]= \frac{19.06}{2}[/tex]

= 9.53 m

Basically we applied the above formulas so that first we easily determined the shortest organ pipe for both ends at this frequency