Answer:
power = 49.95 W
and it is self locking screw
Explanation:
given data
weight W = 100 kg = 1000 N
diameter d = 20mm
pitch p = 2mm
friction coefficient of steel f = 0.1
Gravity constant is g = 10 N/kg
solution
we know T is
T = w tan(α + φ ) [tex]\frac{dm}{2}[/tex] ...................1
here dm is = do - 0.5 P
dm = 20 - 1
dm = 19 mm
and
tan(α) = [tex]\frac{L}{\pi dm}[/tex] ...............2
here lead L = n × p
so tan(α) = [tex]\frac{2\times 2}{\pi 19}[/tex]
α = 3.83°
and
f = 0.1
so tanφ = 0.1
so that φ = 5.71°
and now we will put all value in equation 1 we get
T = 1000 × tan(3.83 + 5.71 ) [tex]\frac{19\times 10^{-3}}{2}[/tex]
T = 1.59 Nm
so
power = [tex]\frac{2\pi N \ T }{60}[/tex] .................3
put here value
power = [tex]\frac{2\pi \times 300\times 1.59}{60}[/tex]
power = 49.95 W
and
as φ > α
so it is self locking screw